Practice question
Question
A spring of \( k = 450 \, \text{N/m} \) has a \( 1.5 \, \text{kg} \) mass. If \( E = 2.25 \, \text{J}
\), what is the amplitude?
Explanation
**Resonance phenomenon** amplifies response when driving frequency matches natural frequency ω_d ≈ ω₀, large amplitude even with small F₀, as damping limits growth. Natural frequency determined by system parameters, resonance condition crucial for understanding vibrations and energy absorption, e.g., bridge collapse, tuning. Total energy: E = (1/2) k A² . 2.25 = 0.5 × 450 × A² ⇒ 2.25 = 225 A² ⇒ A² = 0.01 ⇒ A = 0.1 m . Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and E = ½kA² = ½mω²A², result 0.1 m follows, reflecting SHM dependence on amplitude A, ω and system parameters.
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