Practice question
Question
A particle in SHM has \( x = 6 \cos (4t) \) (in m). What is its maximum acceleration?
Explanation
**Periodic motion** repeats after fixed period T, x(t+T)=x(t), while oscillatory motion involves to-and-fro about equilibrium. SHM is special periodic motion where restoring force proportional to displacement, F = -k x, acceleration a = -ω² x, leading to sinusoidal displacement x = A cos(ωt + φ). Maximum acceleration: aₘₐₓ = ω² A . A = 6 m, ω = 4 s⁻¹ . aₘₐₓ = 4² × 6 = 16 × 6 = 96 m/s² . Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and E = ½kA² = ½mω²A², result 96 m/s² follows, reflecting SHM dependence on amplitude A, ω and system parameters.
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