Practice question

**First law applications** for isobaric W = P ΔV, Q = n C_p ΔT, ΔU = n C_v ΔT, for isothermal ideal gas ΔU=0 Q=W=n R T ln(V₂/V₁), for adiabatic Q=0 W= -ΔU = (P₁V₁ - P₂V₂)/(γ-1), for isochoric W=0 ΔU=Q=n C_v ΔT, enabling calculation of Q,W,ΔU for any process. For an isothermal process, W = μ R T ln((V₂)/(V₁)) .Substitute: μ = 0.1 , R = 8.3 , T = 300 , V₂ = 6 , V₁ = 2 . W = 0.1 × 8.3 × 300 × ln((6)/(2)) = 249 × ln(3) . ln(3) ≈ 1.0986 , so W ≈ 249 × 1.0986