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Question

A circular loop is placed in a uniform magnetic field, and the field strength is increased steadily.
What determines the magnitude of the induced emf in the loop?

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Explanation

**Magnetic flux** Φ = B·A = B A cosθ, B magnetic field (T), A area (m²), θ angle between B and normal to area, unit Wb = T·m², Faraday's law induced emf e = -N dΦ/dt, N turns, negative sign Lenz's law indicating opposition, magnitude |e| = N |ΔΦ/Δt|, for 100 turns ΔΦ=0.03 Wb Δt=0.06 s e=100×0.03/0.06=50 V. According to Faraday’s law, the induced emf depends on the rate of change of magnetic flux, which increases with the rate at which the magnetic field strength changes. Using Φ = B A cosθ, e = -N dΦ/dt = -N A dB/dt = B l v =

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