Practice question

**Inductive reactance calculation** for 60 mH, 50 Hz, X_L=2π×50×0.06=18.85 Ω, V_rms=220 V, I_rms=220/18.85=11.67 A, for 70 mH, 50 Hz, X_L=21.99 Ω, I=110/21.99=5 A, showing X_L ∝ f L, higher f or L increases opposition. X_L = ω L , ω = 2π × 50 = 314 rad/s . L = 65 × 10⁻³ H . X_L = 314 × 0.065 = 20.41 Ω . RMS current: I = (V/X_L) = (230/20.41) ≈ 11.27 A . Peak current: i_m = √(2) I = 1.414 × 11.27 ≈ 15.94 A . Applying X_L = ωL, X_C = 1/ωC, Z = √(R² + (X_L - X_C)²), I_rms =