Practice question
Question
A \( 5 \, \mu\text{F} \) capacitor charged to \( 200 \, \text{V} \) is connected to an uncharged \( 5
\, \mu\text{F} \) capacitor. What is the final potential difference?
Explanation
**Applications** include charge sharing for voltage division, Van de Graaff generator accumulates charge on spherical dome to high potential V = k Q/R, up to MV, using belt to transport charge, capacitance of sphere C=4π ε₀ R ≈10 pF for R=0.1 m, so Q= C V ≈10⁻⁸ C for 1000 V. Initial charge: Q = 5 × 10⁻⁶ × 200 = 10⁻³ C . Total capacitance: 5 + 5 = 10 μF . Final voltage: V = (Q/C) = (10⁻³/10 × 10⁻⁶) = 100 V . Using V = kQ/r, U = k q₁q₂/r, E = -dV/dr, C = ε₀A/d, 1/C_eq series, C_eq = ΣC
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