Practice question

Given: What is the kinetic energy of a 500 kg satellite at 7 R_E from Earth’s nter? ( M_E = 6 × 10²⁴ kg, R_E = 6.4 × 10⁶ m, G = 6.67 × 10⁻¹¹ N m²/kg² ) These values define the system as per NCERT data. Formula: K = G M_E m/2 r. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: r = 7 R_E = 4.48 × 10⁷ m . K = frac6.67 × 10⁻¹¹ × 6 × 10²⁴ × 5002 × 4.48 × 10⁷. K = frac2.001 × 10¹⁷⁸.96 × 10⁷ approx 2.23 × 10⁹ J . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.