Practice question
Question
A double convex lens has radii of curvature 30 cm and -30 cm with refractive index 1.6 . What is its focal length?
Explanation
Given:
A double convex lens has radii of curvature 30 cm and -30 cm with refractive index 1.6 . What is its focal length?
These values define the system as per NCERT data.
Formula:
Lens maker’s formula: 1/f = (n - 1) ( 1/R_1 - 1/R_2 ).
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
n = 1.6, R_1 = 30 cm, R_2 = -30 cm . 1/f = (1.6 - 1) ( 1/30 - 1/-30 ) = 0.6 ( 1/30 + 1/30 ) = 0.6 × 2/30 = 1.2/30 = 1/25 . f = 25 cm .
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
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