Practice question

Given: What is the mass percentage of oxygen in NaNO₃? (Atomic masses: Na = 23, N = 14, O = 16) Formula: Molar mass = 23 + 14 + (3 × 16) = 23 + 14 + 48 = 85 g/mol. Substitution & Calculation: Mass of O = 48 g. % O = (48 / 85) × 100 ≈ 56.47%. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.