Practice question

Given: Two lls of emf 5 V and 7 V with internal resistances 2 Ω and 4 Ω are connected in series with a 6 Ω resistor. What is the current through the circuit? Formula: Equivalent emf: ε_{eq = 5 + 7 = 12 V. Substitution & Calculation: Total resistance: R_{total = 2 + 4 + 6 = 12 Ω . Current: I = fracε_{eqR_{total = 12/12 = 1 A . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.