Practice question

Given: The K_{sp of AgI is 8.3 × 10⁻¹⁷. What is its solubility in 0.01 M NaI ? These values define the system as per NCERT data. Formula: K_{sp = [Ag+][I-], [I-] = 0.01, 8.3 × 10⁻¹⁷= S · 0.01. This is standard NCERT relation. Substitution & Calculation: S = 8.3 × 10⁻¹⁵M. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.