Practice question

Given: The de Broglie wavelength of a particle with momentum 4.0 × 10⁻²⁴ kg m/s is: These values define the system as per NCERT data. Formula: lambda = h/p = frac6.63 × 10⁻³⁴⁴.0 × 10⁻²⁴= 1.6575 × 10⁻¹⁰ m = 0.16575 nm .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.