Practice question

Given: A solenoid has 600 turns per meter and carries a current of 3 A . What is the magnetic field inside it? ( μ_0 = 4 π × 10⁻⁷T m/A ) These values define the system as per NCERT data. Formula: Magnetic field B = μ_0 n I. This is standard NCERT relation. Substitution & Calculation: B = 4 π × 10⁻⁷ × 600 × 3 = 7.2 π × 10⁻⁴approx 2.26 × 10⁻³T . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.