Practice question
Question
The reaction 2X -> Y has an average rate of formation of Y as 4.0 × 10â»â´ mol L^{-1 min^{-1 . What is the rate of disappearance of X in the same units?
Explanation
Given:
The reaction 2X -> Y has an average rate of formation of Y as 4.0 × 10â»â´ mol L^{-1 min^{-1 . What is the rate of disappearance of X in the same units?
These values define the system as per NCERT data.
Formula:
Rate = -1/2 fracΔ[X]Δ t = fracΔ[Y]Δ t.
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
fracΔ[Y]Δ t = 4.0 × 10â»â´, so -fracΔ[X]Δ t = 2 × 4.0 × 10â»â´= 8.0 × 10â»â´.
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
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