Practice question

Given: The mean free path of a gas is 3 × 10⁻⁷ m at a rtain temperature. If the temperature is halved at constant pressure, what is the new mean free path? These values define the system as per NCERT data. Formula: New l = frac3 × 10⁻⁷²= 1.5 × 10⁻⁷ m .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: l propto 1/n, n propto P/T. At constant P, n propto 1/T. If T halved, n doubles, l halves. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.