Practice question

Given: A gas occupies 5 L at 2 atm and 27° C . If the pressure is increased to 4 atm and volume reduced to 3 L, what is the final temperature in Celsius? These values define the system as per NCERT data. Formula: Given: V_1 = 5 L, P_1 = 2 atm, T_1 = 27° C = 300 K, P_2 = 4 atm, V_2 = 3 L. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: P_1 V_1/T_1 = P_2 V_2/T_2 . T_2 = T_1 × P_2/P_1 × V_2/V_1 = 300 × 4/2 × 3/5 = 300 × 2 × 0.6 = 360 K . t_C = T_2 - 273.15 = 360 - 273.15 approx 86.85° C approx 87° C . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.