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Practice question

Question

A brass block of dimensions 0.5 m × 0.2 m × 0.05 m is subjected to a shearing force of 2 × 10⁴ N . If the shear modulus of brass is 3.6 × 10¹⁰ N/m², what is the shear strain?

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Explanation

Given: A brass block of dimensions 0.5 m × 0.2 m × 0.05 m is subjected to a shearing force of 2 × 10⁴ N . If the shear modulus of brass is 3.6 × 10¹⁰ N/m², what is the shear strain? These values define the system as per NCERT data. Formula: Shear modulus: G = fracShear stressShear strain. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Shear stress: Shear stress = F/A, A = 0.5 × 0.2 = 0.1 m² . Shear stress: 2 × 10⁴/0.1 = 2 × 10⁵ N/m² . Shear strain: Shear strain = fracShear stressG = frac2 × 10⁵³.6 × 10¹⁰ approx 5.56 × 10⁻⁶. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

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