Practice question
Question
A brass block of dimensions 0.5 m × 0.2 m × 0.05 m is subjected to a shearing force of 2 × 10ⴠN . If the shear modulus of brass is 3.6 × 10¹ⰠN/m², what is the shear strain?
Explanation
Given:
A brass block of dimensions 0.5 m × 0.2 m × 0.05 m is subjected to a shearing force of 2 × 10ⴠN . If the shear modulus of brass is 3.6 × 10¹ⰠN/m², what is the shear strain?
These values define the system as per NCERT data.
Formula:
Shear modulus: G = fracShear stressShear strain.
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
Shear stress: Shear stress = F/A, A = 0.5 × 0.2 = 0.1 m² . Shear stress: 2 × 10â´/0.1 = 2 × 10âµ N/m² . Shear strain: Shear strain = fracShear stressG = frac2 × 10âµÂ³.6 × 10¹Ⱐapprox 5.56 × 10â»â¶.
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Discussion
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