A hydraulic system applies 150N on a small piston of area 0.015m2. What force is exerted by a large piston of area 0.075
Pascal’s law: P = F1A1 = F2A2. F2 = F1×A2A1. F1 = 150N, A1 = 0.015m2, A2 = 0.075m2. F2 = 150×0.0750.015 = 150×5 = 750N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 750 N. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.