Practice question

Given: A nucleus with mass number 28 has a binding energy of 224 MeV . What is its binding energy per nucleon? These values define the system as per NCERT data. Formula: E_{bn = E_b/A. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: E_b = 224 MeV, A = 28 . E_{bn = 224/28 = 8.0 MeV . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.