Practice question
Question
A 1.8 kg pendulum bob completes a vertical circle of radius 2 m . What is the speed at the top? (Take g = 10 m/s² )
Explanation
Given:
A 1.8 kg pendulum bob completes a vertical circle of radius 2 m . What is the speed at the top? (Take g = 10 m/s² )
These values define the system as per NCERT data.
Formula:
At top, minimum speed v_C = sqrtgL = sqrt10 × 2 = sqrt20 approx 4.47 m/s ..
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
Substituting values like 1.2 × 10â»âµ, 236 J kgâ»Â¹ Kâ»Â¹, CH₃CHâ‚‚NHâ‚‚ etc. into the formula and simplifying step by step.
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Discussion
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