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Practice question

Question

A 1.8 kg pendulum bob completes a vertical circle of radius 2 m . What is the speed at the top? (Take g = 10 m/s² )

Options

Choose one · Correct answer highlighted

Explanation

Given: A 1.8 kg pendulum bob completes a vertical circle of radius 2 m . What is the speed at the top? (Take g = 10 m/s² ) These values define the system as per NCERT data. Formula: At top, minimum speed v_C = sqrtgL = sqrt10 × 2 = sqrt20 approx 4.47 m/s .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

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