Practice question
Question
What is the overall reaction in a mercury ll during discharge?
Explanation
Anode: Zn(Hg) + 2OH- -> ZnO(s) + Hâ‚‚O + 2e- . Cathode: HgO + Hâ‚‚O + 2e- -> Hg(l) + 2OH- . Overall: Zn(Hg) + HgO(s) -> ZnO(s) + Hg(l) . This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.
Discussion
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