Practice question

Given: A solution has a density of 1.22 g/mL and contains 35% by mass H₂SO₄. What is its molarity? (Molar mass of H₂SO₄ = 98 g/mol) These values define the system as per NCERT data. Formula: H₂SO₄ = 35 g. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Assume 100 g solution. . Moles = 35 / 98 ≈ 0.3571 mol. Volume = 100 / 1.22 ≈ 81.97 mL = 0.08197 L. Molarity = 0.3571 / 0.08197 ≈ 4.36 M ≈ 4.4 M. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.