Practice question

Given: A projectile is launched at 45 m/s at 30° . What is its speed at maximum height? (Take g = 10 m/s², cos 30° = 0.866 ) These values define the system as per NCERT data. Formula: At maximum height, speed = v_x = v_0 cos θ_0. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Given: v_0 = 45 m/s, cos 30° = 0.866 . v_x = 45 × 0.866 approx 38.97 m/s . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.