Practice question

Given: A projectile is launched at 10 m/s at 37° . What is its vertical velocity after 1 s ? (Take g = 10 m/s², sin 37° = 0.6 ) These values define the system as per NCERT data. Formula: Vertical velocity v_y = v_0 sin θ_0 - g t. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Given: v_0 = 10 m/s, sin 37° = 0.6, t = 1 s, g = 10 m/s² . v_y = 10 × 0.6 - 10 × 1 = 6 - 10 = -4 m/s . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.