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Question

A car moves at 16m/s and decelerates at 2.5m/s2 for 3s, then accelerates at 3.5m/s2 for 4s. What is the net displacement?

Options

Choose one · Correct answer highlighted

Explanation

Phase 1: v=16−2.5⋅3=8.5m/s, x1=16⋅3−12⋅2.5⋅(3)2=48−11.25=36.75m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 95 m as the result, so option A is correct.