Practice question
Question
A train accelerates uniformly from rest to 15m/s over a distance of 37.5m. What is its acceleration?
Explanation
Use v2=v02+2ax. Here, v0=0, v=15m/s, x=37.5m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 4 m/s² as the result, so option B is correct.