Practice question
Question
A particle starts with velocity 4j^m/s and accelerates at (3i^−2j^)m/s2. What is its speed after 2s?
Explanation
Velocity v=v0+at. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 6 m/s as the result, so option C is correct.