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#water drop

3 public questions tagged with this topic.

Viscosity, Stokes' Law and Reynolds Number

What is the excess pressure inside a water drop of radius 2.5mm at 100∘C? (Surface tension = 0.3×10−3N/m)

Excess pressure: ΔP = 2Sr. S = 0.3×10−3N/m, r = 2.5×10−3m. ΔP = 2×0.3×10−32.5×10−3 = 0.24Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.24 Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Viscosity, Stokes' Law and Reynolds Number

What is the excess pressure inside a water drop of radius 1.8mm at 20∘C? (Surface tension = 0.0727N/m)

Excess pressure: ΔP = 2Sr. S = 0.0727N/m, r = 1.8×10−3m. ΔP = 2×0.07271.8×10−3 = 80.78Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 80 Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Bernoulli's Theorem and Applications

What is the excess pressure inside a water drop of radius 2.5mm at 20∘C? (Surface tension = 0.0727N/m)

Excess pressure: ΔP = 2Sr. S = 0.0727N/m, r = 2.5×10−3m. ΔP = 2×0.07272.5×10−3 = 58.16Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 58 Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

View Details