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Bulk modulus: B = -p / (ΔV / V). Rearrange: ΔV / V = -p / B = -(2 × 106) / (2.2 × 109) ≈ -9.09 × 10-4. Magnitude: 9.09 × 10-4.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Bulk modulus: B = −pΔVV. Rearrange: ΔVV = −pB = −3×1062.2×109≈−1.36×10−3. Magnitude: 1.36×10−3. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.36×10−3. This satisfies dimensional consistency and physical conditions given, so option D is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Bulk modulus: B = −pΔVV. Rearrange: ΔVV = −pB = −1×1062.2×109≈−4.55×10−4. Magnitude: 4.55×10−4. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4.55×10−4. This satisfies dimensional consistency and physical conditions given, so option D is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Bulk modulus: B = −pΔVV. Rearrange: ΔVV = −pB = −2×1062.2×109≈−9.09×10−4. Magnitude: 9.09×10−4. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 9.09×10−4. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Bulk modulus: B = -p / (ΔV / V). Rearrange: p = -B × (ΔV / V). Given: ΔV / V = -0.05% = -0.0005. Substitute: p = 2.2 × 109 × 0.0005 = 1.1 × 106 N/m2.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
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