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Relation: TC = T−273.15. Given: T = 400K. TC = 400−273.15 = 126.85∘C≈127∘C. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 127°C. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
\[J\]=\[M L2T−2\]. 3J=3kg×(1m)2×(1s)−2=3×(4×0.25)×(10×0.1)2×(2×0.5)−2=3×1×1×4=12new units. As per NCERT Class 11 Chapter 2, dimensional analysis checks correctness and SI units define base and derived quantities. This principle confirms that 12 new is correct because its dimensions and unit match the physical quantity asked.
Ref: NCERT Class 11 Physics > Chapter 2: Units and Measurements > Topic: SI Units and Dimensional Formulae
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