A thin uniform ring of mass 2kg and radius 0.5m rotates about its center. What is its moment of inertia?
For a thin ring: I = MR2. M = 2kg, R = 0.5m. I = 2×(0.5)2 = 0.5kg m2. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.5 kg m². This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.