Skip to content
Login Register

#uniform motion

5 public questions tagged with this topic.

Distance, Displacement and Velocity-Time Relations

A truck moving at 144km/h decelerates uniformly and stops in 12s. What is the magnitude of deceleration?

Convert speed: 144km/h=144⋅10003600=40m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 40 m/s as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Distance, Displacement and Velocity-Time Relations

View Details
Distance, Displacement and Velocity-Time Relations

A body moving at 15m/s decelerates uniformly to rest in 5s. What is the distance covered?

Find a=v−v0t=0−155=−3m/s2. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 25 m as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Distance, Displacement and Velocity-Time Relations

View Details
Kinematic Equations and Uniformly Accelerated Motion

A rocket accelerates uniformly from rest at 8m/s2 until it reaches a speed of 40m/s, then maintains that speed for 5s. W

Phase 1 (acceleration): v=v0+at, 40=0+8t⇒t=5s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 300 m as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Kinematic Equations and Uniformly Accelerated Motion

View Details