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#uniform density

4 public questions tagged with this topic.

A uniform triangular lamina has vertices at (0,0), (5,0), and (0,6). What is the x-coordinate of its center of mass?

For a uniform triangular lamina, the center of mass is at the centroid, the average of the vertices. X = 0+5+03 = 53≈1.67m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.67 m. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A uniform rectangular lamina of dimensions 2m×4m and mass 10kg has one corner at the origin along the x- and y-axes. Wha

For a uniform rectangle, the center of mass is at the centroid. Vertices: (0,0),(2,0),(0,4),(2,4). CM: X = 0+22 = 1, Y = 0+42 = 2. Position: (1,2)m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to (1,2). This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

What is the key assumption about Earth’s density in calculating g below its surface?

Considering the Earth has uniform density to simplify the mass contributing to gravity inside (Mr = MEr3RE3), leading to g(d) = g(1−d/RE). Non-uniform density would complicate this. As per NCERT, applying relevant law/formula with correct units and sign convention leads to It is uniform. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.