7 public questions tagged with this topic.
Aniline (C₆H₅NH₂) with H₂SO₄ at high temperature forms p-aminobenzene sulphonic acid (sulphanilic acid), as per the PDF’s chemical properties.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Chemical Reactions - Carbylamine Reaction and General Reactions
Aniline forms anilinium hydrogensulphate, which rearranges on heating to p-aminobenzene sulphonic acid (sulphanilic acid).
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Chemical Reactions - Alkylation, Acylation and Electrophilic Substitution
Aniline (C₆H₅NH₂) forms sulphanilic acid (H₂NC₆H₄SO₃H) with a benzene ring when reacted with H₂SO₄ at high temperature, as per the PDF.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Physical Properties, Basic Character and Solubility
Aniline with concentrated H₂SO₄ at 453-473 K forms sulphanilic acid (p-aminobenzene sulphonic acid) via sulphonation, as per the PDF.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Preparation - Hoffmann Bromamide and Reduction of Nitro Compounds
Aniline (C₆H₅NH₂) undergoes sulphonation with H₂SO₄ at high temperature to form sulphanilic acid (H₂NC₆H₄SO₃H), as per the PDF.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Preparation - Hoffmann Bromamide and Reduction of Nitro Compounds
Phenol reacts with conc. H₂SO₄ at 100°C to form phenol-4-sulfonic acid (4-hydroxybenzenesulfonic acid) via electrophilic substitution at the para position.
Ref: NCERT Class 12 Chemistry > Chapter 7: Alcohols, Phenols and Ethers > Topic: Preparation of Alcohols - from Alkenes Haloalkanes Carbonyls Grignard
Phenol reacts with conc. H₂SO₄ at 25°C to form phenol-2-sulfonic acid (2-hydroxybenzenesulfonic acid) as the major product due to ortho substitution.
Ref: NCERT Class 12 Chemistry > Chapter 7: Alcohols, Phenols and Ethers > Topic: Physical Properties and Acidity of Alcohols and Phenols
