9 public questions tagged with this topic.
S = F2l. F = 2.8×10−2N, l = 0.56m. S = 2.8×10−22×0.56 = 0.025N/m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.025 N/m. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
S = F2l, F = 1.2×10−2N, l = 0.25m. S = 1.2×10−22×0.25 = 0.024N/m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.024 N/m. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
S = F2l. F = 3.0×10−2N, l = 0.5m. S = 3.0×10−22×0.5 = 0.03N/m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.030 N/m. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
S = F2l. F = 2.4×10−2N, l = 0.48m. S = 2.4×10−22×0.48 = 0.025N/m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.025 N/m. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
S = F2l. F = 4.0×10−2N, l = 0.4m. S = 4.0×10−22×0.4 = 0.05N/m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.05 N/m. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
S = F2l. F = 4.8×10−2N, l = 0.48m. S = 4.8×10−22×0.48 = 0.05N/m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.05 N/m. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
S = F2l. F = 1.8×10−2N, l = 0.35m. S = 1.8×10−22×0.35 = 0.0257N/m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.0257 N/m. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
S = F2l. F = 2.2×10−2N, l = 0.44m. S = 2.2×10−22×0.44 = 0.025N/m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.025 N/m. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
S = F2l. F = 3.6×10−2N, l = 0.6m. S = 3.6×10−22×0.6 = 0.03N/m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.030 N/m. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
