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#soap bubble

15 public questions tagged with this topic.

Fluid Pressure, Pascal's Law and Manometers

A soap bubble of radius 6mm has a surface tension of 0.03N/m. What is the excess pressure inside?

Excess pressure in a bubble: ΔP = 4Sr. S = 0.03N/m, r = 6×10−3m. ΔP = 4×0.036×10−3 = 20Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 20 Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Surface Tension, Capillarity and Excess Pressure

A bubble of radius 4mm is formed at 50cm depth in a soap solution (ρ\=1.2×103kg/m3, S\=0.025N/m). What is the total pres

Pi = Pa+ρgh+2Sr. Pa = 1.01×105Pa, ρgh = 1.2×103×9.8×0.5 = 5880Pa. 2Sr = 2×0.0254×10−3 = 12.5Pa. Pi = 1.01×105+5880+12.5 = 1.06892×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.069 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Bernoulli's Theorem and Applications

A soap bubble of radius 8mm has a surface tension of 0.027N/m. What is the excess pressure inside?

Excess pressure in a bubble: ΔP = 4Sr. S = 0.027N/m, r = 8×10−3m. ΔP = 4×0.0278×10−3 = 13.5Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 13.5 Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Equation of Continuity and Flow Rate

A soap bubble of radius 7mm has a surface tension of 0.028N/m. What is the excess pressure inside?

Excess pressure in a bubble: ΔP = 4Sr. S = 0.028N/m, r = 7×10−3m. ΔP = 4×0.0287×10−3 = 16Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 16 Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Equation of Continuity and Flow Rate

A bubble of radius 4.5mm is blown at 35cm depth in a soap solution (ρ\=1.2×103kg/m3, S\=0.025N/m). What is the total pre

Pi = Pa+ρgh+2Sr. Pa = 1.01×105Pa, ρgh = 1.2×103×9.8×0.35 = 4116Pa. 2Sr = 2×0.0254.5×10−3 = 11.11Pa. Pi = 1.01×105+4116+11.11 = 1.05127×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.05 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Fluid Pressure, Pascal's Law and Manometers

A soap bubble of radius 11mm has a surface tension of 0.027N/m. What is the excess pressure inside?

Excess pressure in a bubble: ΔP = 4Sr. S = 0.027N/m, r = 11×10−3m. ΔP = 4×0.02711×10−3 = 9.82Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 10 Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Equation of Continuity and Flow Rate

A soap bubble of radius 10mm has a surface tension of 0.025N/m. What is the excess pressure inside?

Excess pressure in a bubble: ΔP = 4Sr. S = 0.025N/m, r = 10×10−3m. ΔP = 4×0.02510×10−3 = 10Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 10 Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Equation of Continuity and Flow Rate

A bubble of radius 4.0mm is blown at 60cm depth in a soap solution (ρ\=1.2×103kg/m3, S\=0.025N/m). What is the total pre

Pi = Pa+ρgh+2Sr. Pa = 1.01×105Pa, ρgh = 1.2×103×10×0.6 = 7200Pa. 2Sr = 2×0.0254.0×10−3 = 12.5Pa. Pi = 1.01×105+7200+12.5 = 1.082125×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.08 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Equation of Continuity and Flow Rate

A soap bubble of radius 8mm has a surface tension of 0.026N/m. What is the excess pressure inside?

Excess pressure in a bubble: ΔP = 4Sr. S = 0.026N/m, r = 8×10−3m. ΔP = 4×0.0268×10−3 = 13Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 13 Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Equation of Continuity and Flow Rate

A soap bubble of radius 7mm has an excess pressure of 20Pa inside. What is its surface tension?

Excess pressure in a bubble: ΔP = 4Sr. ΔP = 20Pa, r = 7×10−3m. S = ΔP⋅r4 = 20×7×10−34 = 0.035N/m. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.035 N/m. This satisfies dimensional consistency and physical conditions given, so option D is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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Fluid Pressure, Pascal's Law and Manometers

A soap bubble of radius 15mm has a surface tension of 0.023N/m. What is the excess pressure inside?

Excess pressure in a bubble: ΔP = 4Sr. S = 0.023N/m, r = 15×10−3m. ΔP = 4×0.02315×10−3 = 6.13Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 6 Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.

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