What is the total pressure at a depth of 4m in seawater (ρ\=1.03×103kg/m3) if atmospheric pressure is 1.01×105Pa? (Take
Total pressure: P = Pa+ρgh. Pa = 1.01×105Pa, ρ = 1.03×103kg/m3, g = 9.8m/s2, h = 4m. P = 1.01×105+1.03×103×9.8×4 = 1.01×105+40376 = 1.41376×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.41 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option A is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.