A thin ring of mass 2kg and radius 0.7m rolls without slipping with a linear speed of 3.5m/s. What is its angular veloci
v = ωr. v = 3.5m/s, r = 0.7m. ω = vr = 3.50.7 = 5rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.