8 public questions tagged with this topic.
For rolling without slipping: v = ωr. v = 2m/s, r = 0.2m. ω = vr = 20.2 = 10rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 10 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
Angular momentum: L = Iω. For a solid cylinder: I = 12MR2 = 12×10×(0.5)2 = 1.25kgm2. ω = LI = 251.25 = 20rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 20 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
v = ωr. ω = 4rad/s, r = 0.5m. v = 4×0.5 = 2m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.0 m/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
v = ωr. ω = 8rad/s, r = 0.4m. v = 8×0.4 = 3.2m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.2 m/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
For rolling without slipping, the linear velocity of the center of mass (v) equals the product of angular velocity (ω) and radius (r): v = ωr. As per NCERT, applying relevant law/formula with correct units and sign convention leads to v\=ωr. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
Rolling motion combines translation (motion of the center) and rotation about an axis, while pure rotational motion involves only rotation about a fixed axis without translation. As per NCERT, applying relevant law/formula with correct units and sign convention leads to Rolling motion combines translation and rotation. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
v = ωr. ω = 6rad/s, r = 0.8m. v = 6×0.8 = 4.8m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4.8 m/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
v = ωr. v = 5m/s, r = 0.5m. ω = vr = 50.5 = 10rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 10 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
