A car decelerates uniformly from 25m/s to rest over a distance of 62.5m. What is the deceleration?
Use v2=v02+2ax. Here, v=0, v0=25m/s, x=62.5m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 62.5 m as the result, so option A is correct.
Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Uniform Acceleration and Graphical Analysis