The compound formed when ethylamine reacts with chloroform and alcoholic KOH is:
Ethylamine (CH₃CH₂NH₂) undergoes the carbylamine reaction with CHCl₃ and alcoholic KOH to form ethyl isocyanide (CH₃CH₂NC), as per the PDF.
Ref: NCERT Class 12 Chemistry > Chapter 13: Amines > Topic: Preparation - Hoffmann Bromamide and Reduction of Nitro Compounds