A horizontal pipe carries water (ρ\=1000kg/m3) at 2m/s and 1.4×105Pa. If the speed becomes 5m/s, what is the pressure?
Bernoulli’s equation: P1+12ρv12 = P2+12ρv22. P1 = 1.4×105Pa, v1 = 2m/s, v2 = 5m/s, ρ = 1000kg/m3. P2 = 1.4×105+12×1000(4−25) = 1.4×105−10500 = 1.295×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.295 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.