10 public questions tagged with this topic.
I = MR2 = 1×(0.2)2 = 0.04kg m2. K = 12Iω2⇒2 = 12×0.04×ω2⇒4 = 0.04ω2⇒ω2 = 100⇒ω = 10rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 10 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = MR2 = 4×(0.6)2 = 1.44kg m2. L = Iω = 1.44×5 = 7.2kg m2/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 7.2 kg m²/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = MR2 = 5×(0.2)2 = 0.2kg m2. K = 12Iω2 = 12×0.2×(10)2 = 0.1×100 = 10J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 10 J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = MR2 = 2×(0.5)2 = 0.5kg m2. ω = LI = 100.5 = 20rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 20 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = MR2 = 2×(0.8)2 = 1.28kg m2. ω = LI = 161.28 = 12.5rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 12.5 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
I = MR2 = 3×(0.2)2 = 0.12kg m2. L = Iω = 0.12×15 = 1.8kg m2/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.8 kg m²/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
v = ωr. ω = 8rad/s, r = 0.4m. v = 8×0.4 = 3.2m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 3.2 m/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
v = ωr. v = 3m/s, r = 0.6m. ω = vr = 30.6 = 5rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
v = ωr. ω = 6rad/s, r = 0.8m. v = 6×0.8 = 4.8m/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4.8 m/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
For a hollow cylinder: I = MR2 = 3×(0.3)2 = 0.27kg m2. KE: K = 12Iω2 = 12×0.27×(6)2 = 0.135×36 = 4.86J≈4.9J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4.9 J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
