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#glycerine

2 public questions tagged with this topic.

A sphere of radius 0.02m falls through glycerine (η\=0.83Pa s) at a terminal velocity of 0.1m/s. What is the viscous dra

Using Stokes’ law: F = 6πηav. η = 0.83Pa s, a = 0.02m, v = 0.1m/s. F = 6×3.14×0.83×0.02×0.1≈0.0313N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.031 N. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A sphere of radius 0.06m moves at 0.13m/s through glycerine (η\=0.83Pa s). What is the viscous drag force?

Stokes’ law: F = 6πηav. η = 0.83Pa s, a = 0.06m, v = 0.13m/s. F = 6×3.14×0.83×0.06×0.13 = 0.1222N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.12 N. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.