A sphere of radius 0.02m falls through glycerine (η\=0.83Pa s) at a terminal velocity of 0.1m/s. What is the viscous dra
Using Stokes’ law: F = 6πηav. η = 0.83Pa s, a = 0.02m, v = 0.1m/s. F = 6×3.14×0.83×0.02×0.1≈0.0313N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 0.031 N. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.