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Question

A thin ring of mass 6kg and radius 0.3m rotates at 5rad/s. What is its angular momentum?

Options

Choose one · Correct answer highlighted

Explanation

I = MR2 = 6×(0.3)2 = 0.54kg m2. L = Iω = 0.54×5 = 2.7kg m2/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.7 kg m²/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.