Practice question
Question
A particle starts with velocity 5i^m/s and accelerates at (−3j^)m/s2. What is its displacement magnitude after 2s?
Explanation
Displacement r=v0t+12at2. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 10 m as the result, so option A is correct.