Practice question
Question
A gas at 3atm and 27∘C occupies 4L. If the pressure is reduced to 1.5atm and temperature raised to 177∘C, what is the new volume?
Explanation
Given: P1 = 3atm, T1 = 27∘C = 300K, V1 = 4L, P2 = 1.5atm, T2 = 177∘C = 450K. P1V1T1 = P2V2T2. V2 = V1×P1P2×T2T1 = 4×31.5×450300 = 4×2×1.5 = 12L.