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Practice question

MCQ

Question

A brass wire of length 3 m and cross-sectional area 2 × 10-6 m2 is stretched by a force of 400 N. If the Young's modulus of brass is 9 × 1010 N/m2, what is the elongation?

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Explanation

Young's modulus: Y = (F L) / (A ΔL). Rearrange: ΔL = (F L) / (A Y). Substitute: ΔL = (400 × 3) / (2 × 10-6 × 9 × 1010) = 1200 / (1.8 × 105) = 6.67 × 10-3 m ≈ 6.67 mm.

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