Practice question
Question
A ball is thrown vertically upwards with an initial speed of 28m/s. What is the total time of flight? (Take g\=10m/s2)
Explanation
Time to max height: v=v0+at, 0=28−10t⇒t=2.8s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 2.8 s as the result, so option A is correct.