Practice question
Question
A ball is thrown upwards with a speed of 48m/s. How long does it take to return to the ground? (Take g\=10m/s2)
Explanation
Time to max height: v=v0+at, 0=48−10t⇒t=4.8s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 4.8 s as the result, so option A is correct.